-.05x^2+2.7x+5.8=0

Solution for -.05x^2+2.7x+5.8=0 equation:

-.05x^2+2.7x+5.8=0

We add all the numbers together, and all the variables

-0.05x^2+2.7x+5.8=0

a = -0.05; b = 2.7; c = +5.8;
Δ = b2-4ac
Δ = 2.72-4·(-0.05)·5.8
Δ = 8.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.7)-\sqrt{8.45}}{2*-0.05}=\frac{-2.7-\sqrt{8.45}}{-0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.7)+\sqrt{8.45}}{2*-0.05}=\frac{-2.7+\sqrt{8.45}}{-0.1}
$